A magnetic coil, which made from copper have constant voltage. In operation the temperature is going higher from 12 degrees Celsius to 60 degrees Celsius. How much percentage has the electric current changed by the warming of the coil?
bonus. how much is the percentage of the resistor?
What we know?
voltage is constant
This function about how to search resistor from a certain temperature

= Resistor from temperature theta

= Resistor from referenced temperature

= coefficient from temperature which depend on the material

= referenced temperature (in most case 20 degrees Celsius)
what do we need to calculate
okay here is the answer
that is the way to search the resistor's percentage
then move to electric current
with that we can search for the percentage
![\120dpi \large \frac{\bigtriangleup I}{I_{12}}=\frac{\frac{-U\times(R_{12}\times R_{60})}{R_{60}\times R_{12}}}{\frac{U}{R_{12}}}=\frac{-R_{12}\times R_{60}}{R_{12}}=\\\frac{-R_{20}[\alpha_{20}(12-60)]}{R_{20}[1+\alpha_{20}(60-12)]}=\\\frac{-\alpha_{20}(12-60)}{1+\alpha_{20}(60-12)}=0,16](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tyGUBNej5wgdfuOA4dGTe3036bkARpfH7n_zKmkFGl-t2kIMA6zRtIEYOvzaTyY67L-3jZyLmY-v9BKbkOGwZJwH4uiBCOgSzDLdzLCeej5r9g7NaH6G9tm5NWaPAGy08Zy45ayR-tBAeUfiFJJt8BIkJtoKu1K8cITIwjpD_xfBxALBJADZRS2wUoohYs8S7M4QIlvRHLGNcwTvDmh92mlumZZEl7NLCF_Zky0zsnHbNOWpxxzAPsNT2FpvKQv8FcHlFugSC0S3Ag66Zcp1IJ08h4J3rlBEiauJPpLbegw89Kpz8joMhdxQb7aAy7GxBzhU-3y2eRLaQagIpE9T0aD7rswJNTcymwhDAWdQ0rApyV3kQM5EyQ846GzJ-u3hfhqSR499RrhCc0TQrnMSPD3yIay2tj0qv9xhof988E0RzBCnVD49EuZiAMbbKhJOG7gvVPE7xwbWDU38eEWjB10lhJ35E2Oxx8BfaKKrhQOGU-i_hklbkFeuyQok4OHVP0veVOPX_RApij9LqOD6Fzdvm-HXfqKd9KL3WZiBgaNazoL7hGputShgr2qxPWazNCuem_GD851LWkz5ud41cZ2K3DlvonKauS-23t00VstE3-tOcRoJghTfVz5-CN9OIDGJn-Rx8wXmtZ3opepsumSNQwLIfZ-MYXf1-NifS3OCcxzPF8gFQLW6j_Cp8iFQ1JM7_NfaZ2cw=s0-d)
thats all. 19% change on resistor and 16% on Electric current.
headfake from this post.
- use Latex for this mathematic calculation
- thanks to codecogs for letting me write latex on blogspot
- i use lyx to get better view of what i calculate
- it also give me another project about how to install latex plugin on Ubuntu
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